Thermodynamics Question 98

Question: If at 298 K the bond energies of CH,CC, C=C and HH bonds are respectively 414, 347, 615 and 435 kJ mol1 , the value of enthalpy change for the reaction H2C=CH2(g)+H2(g)H3CCH3(g) at 298 K will be [AIEEE 2003]

Options:

A) + 250 kJ

B) ? 250 kJ

C) + 125 kJ

D) ? 125 kJ

Show Answer

Answer:

Correct Answer: D

Solution:

CH2=CH2(g)+H2(g)H3CCH3(g)

414×4=1656

414×6=2484

615×1=615

347×1=347

435×1=4352706 2831 ΔH=27062831=125kJ



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