Thermodynamics Question 92

Question: The equilibrium constant of a reaction at $ 298K $ is $ 5\times {{10}^{-3}} $ and at $ 1000K $ is $ 2\times {{10}^{-5}} $ . What is the sign of $ \Delta H $ for the reaction

[Pb. CET 1998]

Options:

A) $ \Delta H=0 $

B) $ \Delta H $ is negative

C) $ \Delta H $ is positive

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

Equilibrium constant is decreases with temperature and $ \Delta H $ is also decreases so it is -ve.



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