SATHEE: Thermodynamics Question 88

Thermodynamics Question 88

Question: $C_{(graphite)} + O_{2} (g) \to C O_{2} (g)$

$Δ H = - 94.05 k c a l m o l^{- 1}$

$C_{(diamond)} + O_{2} (g) \to C O_{2} (g);$

$Δ H = - 94.50 k c a l m o l^{- 1}$ therefore [DPMT 2001]

Options:

A) $C_{(graphite)} \to C_{(diamond)}$ ; $Δ H_{298 K}^{o} = - 450 c a l m o l^{- 1}$

B) $C_{(diamond)} \to C_{(graphite)};$

$Δ H_{298 K}^{o} = + 450 c a l m o l^{- 1}$

C) Graphite is the stabler allotrope

D) Diamond is harder than graphite

Show Answer

Answer:

Correct Answer: C

Solution:

Heat energy is also involved when one allotropic form of an element is converted in to another. graphite is the stabler allotrope because the heat of transformation of

$C_{(d i a m o n d)} \to C_{(g r a p h i t e)}$ . (i)

$C_{(d i a)} + O_{2 (g)} = C O_{2 (g)} Δ H = - 94.5 k c a l$ (ii)

$C_{(g r a p h i t e)} + O_{2 (g)} = C O_{2 (g)} Δ H = - 94.0 k c a l$

$Δ H_{t r a n s f o r m a t i o n} = - 94.5 - (- 94.0)$

$= - 0.5 k c a l$ .

Thermodynamics Question 88

Question: $C_{(graphite)} + O_{2} (g) \to C O_{2} (g)$

Options:

Answer:

Solution:

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Thermodynamics Question 88

Question: C(graphite)+O2(g)→CO2(g)

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: $C_{(graphite)} + O_{2} (g) \to C O_{2} (g)$