Thermodynamics Question 84

Question: The enthalpy of neutralization of $ HCN $ by $ NaOH $ is $ -12.13kJmo{{l}^{-1}} $ . The enthalpy of ionisation of $ HCN $ will be

[BHU 1997]

Options:

A) 4.519 kJ

B) 45.10 kJ

C) 451.9 kJ

D) 45.19 kJ

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Answer:

Correct Answer: D

Solution:

$ Q=18.94\times 0.632\times 0.998\times 1000 $

$ -57.4+x=-12.13 $

$ x=45.2 $



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