SATHEE: Thermodynamics Question 84

Thermodynamics Question 84

Question: The enthalpy of neutralization of $H C N$ by $N a O H$ is $- 12.13 k J m o l^{- 1}$ . The enthalpy of ionisation of $H C N$ will be

[BHU 1997]

Options:

A) 4.519 kJ

B) 45.10 kJ

C) 451.9 kJ

D) 45.19 kJ

Show Answer

Answer:

Correct Answer: D

Solution:

$Q = 18.94 \times 0.632 \times 0.998 \times 1000$

$- 57.4 + x = - 12.13$

$x = 45.2$

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Thermodynamics Question 84

Question: The enthalpy of neutralization of HCN by NaOH is −12.13kJmol−1 . The enthalpy of ionisation of HCN will be

Options:

Answer:

Solution:

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Question: The enthalpy of neutralization of $H C N$ by $N a O H$ is $- 12.13 k J m o l^{- 1}$ . The enthalpy of ionisation of $H C N$ will be