Thermodynamics Question 6

Question: The pressure and density of a diatomic gas $ (\gamma =7/5) $ change adiabatically from (P, d) to (P’, d’). If $ \frac{d’}{d}=32 $ , then $ \frac{P’}{P} $ should be

[CPMT 1982; EAMCET 2001]

Options:

A) $ \frac{24}{5} $

B) 8

C) $ \frac{40}{3} $

D) 32 times its initial pressure

Show Answer

Answer:

Correct Answer: D

Solution:

$ P{{V}^{\gamma }} $ =constant

Therefore $ \frac{P _{2}}{P _{1}}={{( \frac{V _{1}}{V _{2}} )}^{\gamma }}\Rightarrow P _{2}={{(8)}^{5/3}}P _{1}=32\ P _{1} $



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