Thermodynamics Question 56
Question: Heat of neutralization of strong acid against strong base is constant and is equal to
[EAMCET 1980; AFMC 1989; DPMT 1991; MP PET 1999; BHU 1999; MP PMT 1995]
Options:
A) 13.7 kcal
B) 57 kJ
C) $ 5.7\times 10^{4} $ J
D) All of the above
Show Answer
Answer:
Correct Answer: D
Solution:
$ 13.7kcal=57kJ=5.7\times 10^{4}J $ .
