Thermodynamics Question 53

Question: For an adiabatic expansion of a perfect gas, the value of $ \frac{\Delta P}{P} $ is equal to

[CPMT 1983; MP PMT 1990]

Options:

A) $ 1.8\times 10^{5}N/m^{2} $

B) $ 1.5\times 10^{5}N/m^{2} $

C) $ 1.4\times 10^{5}N/m^{2} $

D) $ 1.2\times 10^{5}N/m^{2} $

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Answer:

Correct Answer: B

Solution:

$ \frac{\text{Adiabatic elasticicity}\ ({E _{\varphi }})}{\text{Isothermal}\ \text{elasticicity}\ ({E _{\theta }})}=\gamma $

Therefore $ {E _{\theta }}=\frac{{E _{\varphi }}}{\gamma } $

Therefore $ {E _{\theta }}=\frac{2.1\times 10^{5}}{1.4} $

$ =1.5\times 10^{5}N/m^{2} $



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