Thermodynamics Question 52

Question: Adiabatic modulus of elasticity of a gas is $ 2.1\times 10^{5}N/m^{2}. $ What will be its isothermal modulus of elasticity $ ( \frac{C _{p}}{C _{v}}=1.4 ) $

[UPSEAT 1999]

Options:

A) Zero

B) 100J

C) - 50J

D) 50J

Show Answer

Answer:

Correct Answer: D

Solution:

For adiabatic forces $ \Delta W=-\Delta U $

$ (\because \Delta Q=0) $

Therefore $ \Delta W=-(-50)=+50J $



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