Thermodynamics Question 45
Question: The internal energy of the gas increases In
[MP PMT 1989; RPMT 2001]
Options:
A) $ {{2}^{0.7}}\times 10^{5} $
B) $ {{2}^{1.3}}\times 10^{5} $
C) $ {{2}^{1.4}}\times 10^{5} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ \because \ P{{V}^{\gamma }}=k $ (constant)
Therefore $ P _{1}V _{1}^{\gamma }=P _{2}V _{2}^{\gamma } $
Therefore $ P _{2}=P _{1}{{( \frac{V _{1}}{V _{2}} )}^{\gamma }}=10^{5}\times {{(2)}^{1.3}} $
$ (\because \ V _{2}=\frac{V _{1}}{2}) $
