SATHEE: Thermodynamics Question 45

Thermodynamics Question 45

Question: The internal energy of the gas increases In

[MP PMT 1989; RPMT 2001]

Options:

A) $2^{0.7} \times 10^{5}$

B) $2^{1.3} \times 10^{5}$

C) $2^{1.4} \times 10^{5}$

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

$∵ P V^{γ} = k$ (constant)

Therefore $P_{1} V_{1}^{γ} = P_{2} V_{2}^{γ}$

Therefore $P_{2} = P_{1} {(\frac{V_{1}}{V_{2}})}^{γ} = 10^{5} \times {(2)}^{1.3}$

$(∵ V_{2} = \frac{V_{1}}{2})$

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Thermodynamics Question 45

Question: The internal energy of the gas increases In

Options:

Answer:

Solution:

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