Thermodynamics Question 43
Question: A gas is suddenly compressed to 1/4 th of its original volume at normal temperature. The increase in its temperature is $ (\gamma =1.5) $
[DCE 2004]
Options:
A) $ (T+2.4)K $
B) $ (T-2.4)K $
C) $ (T+4)K $
D) $ (T-4)K $
Show Answer
Answer:
Correct Answer: D
Solution:
$ W=\frac{R(T _{i}-T _{f})}{\gamma -1} $
Therefore $ 6R=\frac{R(T-T _{f})}{( \frac{5}{3}-1 )} $
Therefore $ T _{f}=(T-4)K. $
