SATHEE: Thermodynamics Question 43

Thermodynamics Question 43

Question: A gas is suddenly compressed to 1/4 th of its original volume at normal temperature. The increase in its temperature is $(γ = 1.5)$

[DCE 2004]

Options:

A) $(T + 2.4) K$

B) $(T - 2.4) K$

C) $(T + 4) K$

D) $(T - 4) K$

Show Answer

Answer:

Correct Answer: D

Solution:

$W = \frac{R (T_{i} - T_{f})}{γ - 1}$

Therefore $6 R = \frac{R (T - T_{f})}{(\frac{5}{3} - 1)}$

Therefore $T_{f} = (T - 4) K .$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Thermodynamics Question 43

Question: A gas is suddenly compressed to 1/4 th of its original volume at normal temperature. The increase in its temperature is (γ=1.5)

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

Question: A gas is suddenly compressed to 1/4 th of its original volume at normal temperature. The increase in its temperature is $(γ = 1.5)$