Thermodynamics Question 39
Question: Air is filled in a motor tube at $ 27^{o}C $ and at a pressure of $ 8 $ atmospheres. The tube suddenly bursts, then temperature of air is $ [\text{Given}\gamma \text{of}\text{air}=1.5] $
[MP PMT 2002]
Options:
A) $ 627^{o}C $
B) $ 527^{o}C $
C) $ 427^{o}C $
D) $ 327^{o}C $
Show Answer
Answer:
Correct Answer: D
Solution:
Using relation$ \frac{T _{2}}{T _{1}}={{( \frac{P _{2}}{P _{1}} )}^{\frac{\gamma -1}{\gamma }}}={{(8)}^{\frac{3/2-1}{3/2}}}=2 $ .
Therefore $ T _{2}=2T _{1} $
Therefore $ T _{2}=2(273+27)=600K=327{}^\circ C $
