Thermodynamics Question 37

Question: ΔU+ΔW=0 is valid for

[RPMT 2000]

Options:

A) 420K

B) 327oC

C) 300K

D) 142oC

Show Answer

Answer:

Correct Answer: D

Solution:

TγP1γ= constant

Therefore TPγ1γ

Therefore T2T1=(P2P1)γ1γ=(18)5/315/3

T2=300×(18)0.4=131K=142C



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