Thermodynamics Question 366

Question: An ideal gas heat engine operates in a Carnot’s cycle between $ 227^{o}C $ and $ 127^{o}C $ . It absorbs 6 × 104 J at high temperature. The amount of heat converted into work is ….

Options:

A) $ 4.8\times 10^{4}J $

B) $ 3.5\times 10^{4}J $

C) $ 1.6\times 10^{4}J $

D) $ 1.2\times 10^{4}J $

Show Answer

Answer:

Correct Answer: D

Solution:

[d]$ \eta =1-\frac{T _{2}}{T _{1}}=1-\frac{400}{500}=\frac{1}{5} $

$ \because \ \eta =\frac{W}{Q} $

Therefore $ \frac{1}{5}=\frac{W}{Q} $

Therefore $ W=\frac{Q}{5}=\frac{6}{5}\times 10^{4}=1.2\times 10^{4}J $



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