Thermodynamics Question 361

Question: A diatomic gas initially at 18°C is compressed adiabatically to one-eighth of its original volume. The temperature after compression will be

Options:

A) $ 10^{o}C $

B) $ 887^{o}C $

C) $ 668K $

D) $ 144^{o}C $

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Answer:

Correct Answer: C

Solution:

[c]$ T{{V}^{\gamma -1}}= $ constant $ \Rightarrow T _{2}=T _{1}{{( \frac{V _{1}}{V _{2}} )}^{\gamma -1}}=(273+18)\ {{( \frac{V}{V/8} )}^{0.4}}=668K $



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