Thermodynamics Question 334

Question: For a cyclic process A→B→C→A, the following information is given Path ΔQ (Heat supplied) ΔU (Increase in internal energy) Work done by system on surrounding
A→B 600 J 200 J 400 J
B→C - 100 J 100 J - 200 J
C→A - 100 J - 300 J 200 J
Calculate the heat of the cycle and efficiency of cycle.

Options:

A) 400 J, 100%

B) 600 J, 66.67%

C) 400 J, 66.67%

D) 600 J, 100%

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Heat of cycle = Net heat =600−200=400J Efficiency η=WorkdoneHeatsupplied=400600 =66.67

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