Thermodynamics Question 334
Question: For a cyclic process $ A\to B\to C\to A, $ the following information is given Path $ \Delta Q $ (Heat supplied) $ \Delta U $ (Increase in internal energy) Work done by system on surrounding
| $ A\to B $ 600 J 200 J 400 J | |
| $ B\to C $ - 100 J 100 J - 200 J | |
| $ C\to A $ - 100 J - 300 J 200 J | |
| Calculate the heat of the cycle and efficiency of cycle. |
Options:
A) 400 J, 100%
B) 600 J, 66.67%
C) 400 J, 66.67%
D) 600 J, 100%
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Answer:
Correct Answer: C
Solution:
[c] Heat of cycle = Net heat $ =600-200=400J $ Efficiency $ \eta =\frac{\text{Work}\text{done}}{\text{Heat}\text{supplied}}=\frac{400}{600} $ $ =66.67% $
