SATHEE: Thermodynamics Question 333

Thermodynamics Question 333

Question: A gas expands with temperature according to the relation $V = k T^{2 / 3}$ . Calculate work done when the temperature changes by 60 K?

Options:

A) 10 R

B) 30 R

C) 40 R

D) 20 R

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $d W = p d V = \frac{R T}{V} d V$ .. (i)

As, $V = k T^{2 / 3}, d V = k \frac{2}{3} T^{- 2 / 3} d T$

$\frac{d V}{V} = \frac{k \frac{2}{3} T^{- 2 / 3} d T}{k T^{2 / 3}} = \frac{2}{3} \frac{d T}{T}$

From Eq. (i), $W = \int_{T_{1}}^{T_{2}} R T \frac{d V}{V} = \int_{T_{1}}^{T_{2}} R T \frac{2}{3} \frac{d T}{T}$

$W = \frac{2}{3} R (T_{2} - T_{1})$

$= \frac{2}{3} R \times 60 = 40 R$

Thermodynamics Question 333

Question: A gas expands with temperature according to the relation $V = k T^{2 / 3}$ . Calculate work done when the temperature changes by 60 K?

Options:

Answer:

Solution:

Engineering Preparation

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Other Resources

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Sample Mock Test

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Thermodynamics Question 333

Question: A gas expands with temperature according to the relation V=kT2/3 . Calculate work done when the temperature changes by 60 K?

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: A gas expands with temperature according to the relation $V = k T^{2 / 3}$ . Calculate work done when the temperature changes by 60 K?