SATHEE: Thermodynamics Question 328

Thermodynamics Question 328

Question: An ideal refrigerator has a freezer at a temperature of $- 13^{\circ} C$ . The coefficient of performance of the engine is 5. The temperature of the air (to which heat is rejected) is.

Options:

A) $320^{\circ} C$

B) $39^{\circ} C$

C) 325 K

D) $325^{\circ} C$

Show Answer

Answer:

Correct Answer: B

Solution:

[b]Given $β = 5$

We have, $β = \frac{T_{2}}{T_{1} - T_{2}}$

where $T_{1} =$ temp. of surrounding,

$T_{2} =$ temp. of cold body

$= - 13^{0} C = (- 13 + 273) K = 260 K$

or $5 = \frac{260}{T_{1} - 260}$

$5 T_{1} = 260 + 1300$ or $T_{1} = 312 K = 39^{o} C$ .

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Thermodynamics Question 328

Question: An ideal refrigerator has a freezer at a temperature of −13∘C . The coefficient of performance of the engine is 5. The temperature of the air (to which heat is rejected) is.

Options:

Answer:

Solution:

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Question: An ideal refrigerator has a freezer at a temperature of $- 13^{\circ} C$ . The coefficient of performance of the engine is 5. The temperature of the air (to which heat is rejected) is.