Thermodynamics Question 318

Question: An imaginary ideal gas with adiabatic exponent $ \gamma =2 $ goes through a cycle . Find efficiency of cycle:

Options:

A) $ \frac{1}{9} $

B) $ \frac{1}{8} $

C) $ \frac{1}{6} $

D) $ \frac{1}{5} $

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Answer:

Correct Answer: A

Solution:

[a]$ \eta =\frac{w}{Q _{given}}=\frac{\frac{p _{0}v _{0}}{2}}{\frac{1}{2}(p _{0}+2p _{0})v _{0}+\frac{nR\Delta T}{2-1}} $ $ =\frac{\frac{p _{0}v _{0}}{2}}{\frac{3p _{0}v _{0}}{2}+4p _{0}v _{0}-p _{0}v _{0}}=\frac{1}{9} $



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