Thermodynamics Question 316

Question: Two carnot’s engines A and B are operated in series. The first one A receives heat at 1200 K and rejects to a reservoir at T and K. The second engine B receives the heat rejected by the first engine and in turn rejects to a heat reservoir at 300 K. Calculate the value of T, when work outputs of the two engines are equal.

Options:

A) 600 K

B) 750 K

C) 450 K

D) 900 K

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Answer:

Correct Answer: B

Solution:

[b]$ \frac{W}{Q _{1}+W}={\eta _{1}} $

$ \frac{W}{Q _{1}}={\eta _{2}} $

$ \frac{W}{Q _{1}}=1-\frac{300}{T} $

$ \Rightarrow $ $ \frac{1}{1+\frac{T}{T-300}}=\frac{1200-T}{1200} $

$ \Rightarrow $ $ (T-300)1200=(1200-T)(2T-300) $

$ T=750K $



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