Thermodynamics Question 31

Question: At N.T.P. one mole of diatomic gas is compressed adiabatically to half of its volume$ \gamma =1.41 $ . The work done on gas will be

[RPET 1997]

Options:

A) $ C _{V}(T _{i}-T _{f}) $

B) $ C _{P}(T _{i}-T _{f}) $

C) $ \frac{1}{2}(C _{P}+C _{V})(Ti-T _{f}) $

D) $ (C _{P}-C _{V})(T _{i}-T _{f}) $

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Answer:

Correct Answer: A

Solution:

$ \Delta U=\mu C _{V}\Delta T=1\times C _{V}(T _{f}-T _{i})=-C _{V}(T _{i}-T _{f}) $

Therefore |DU| = CV (Ti - Tf)



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