SATHEE: Thermodynamics Question 31

Thermodynamics Question 31

Question: At N.T.P. one mole of diatomic gas is compressed adiabatically to half of its volume $γ = 1.41$ . The work done on gas will be

[RPET 1997]

Options:

A) $C_{V} (T_{i} - T_{f})$

B) $C_{P} (T_{i} - T_{f})$

C) $\frac{1}{2} (C_{P} + C_{V}) (T i - T_{f})$

D) $(C_{P} - C_{V}) (T_{i} - T_{f})$

Show Answer

Answer:

Correct Answer: A

Solution:

$Δ U = μ C_{V} Δ T = 1 \times C_{V} (T_{f} - T_{i}) = - C_{V} (T_{i} - T_{f})$

Therefore |DU| = CV (Ti - Tf)

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Thermodynamics Question 31

Question: At N.T.P. one mole of diatomic gas is compressed adiabatically to half of its volumeγ=1.41 . The work done on gas will be

Options:

Answer:

Solution:

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Question: At N.T.P. one mole of diatomic gas is compressed adiabatically to half of its volume $γ = 1.41$ . The work done on gas will be