Thermodynamics Question 301

Question: The efficiency of an ideal gas with adiabatic exponent γ for the shown cyclic process would be

Options:

A) (2ln21)γ/(γ1)

B) (12ln2)γ/(γ1)

C) (2ln2+1)γ/(γ1)

D) (2ln21)γ/(γ+1)

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Answer:

Correct Answer: A

Solution:

[a] WAB=0,WBC=PΔV=nRΔT=nRT0

WCA=nRTnVfVi=nR(2T0)n2

QBC=nCpΔT=(nRγγ1)T0

Efficieancy, η=WQ=[2n21γ/(γ1)]



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