Thermodynamics Question 299

Question: When 1 kg of ice at $ 0{}^\circ C $ melts to water at $ 0{}^\circ C, $ the resulting change in its entropy, taking latent heat of ice to be 80 cal/$ {}^\circ C $ , is

Options:

A) 273 cal/K

B) 253 cal/K

C) 263 cal/K

D) 293 cal/K

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Answer:

Correct Answer: D

Solution:

[d] Change in entropy is given by $ dS=\frac{dQ}{T}\text{ or }\Delta S=\frac{\Delta Q}{T}=\frac{mL _{f}}{273} $

$ \Delta S=\frac{1000\times 80}{273}=293\text{ cal/K}\text{.} $



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