Thermodynamics Question 295

Question: 1 gm of water at a pressure of 1.01×105 Pa is converted into steam without any change of temperature. The volume of 1 g of steam is 1671 cc and the latent heat of evaporation is 540 cal. The change in internal energy due to evaporation of 1 gm of water is

Options:

A) 167cal

B) 500cal

C) 540 cal

D) 58 cal

Show Answer

Answer:

Correct Answer: B

Solution:

[b] dW=PΔV=1.01×105[16711]×106Joule

=1.01×1674.2cal.=40cal. nearly

ΔQ=mL=1×540.

ΔQ=ΔW+ΔU

or ΔU=54040=500 cal



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