Thermodynamics Question 29
Question: A cycle tyre bursts suddenly. This represents an
[SCRA 1994]
Options:
A) $ 108^{o}C $
B) $ 9327^{o}C $
C) $ 1200^{o}C $
D) $ 927^{o}C $
Show Answer
Answer:
Correct Answer: D
Solution:
$ T{{V}^{\gamma -1}}= $ constant$ \Rightarrow T _{2}=T _{1}{{( \frac{V _{1}}{V _{2}} )}^{\gamma -1}}=927^{o}C $