Thermodynamics Question 29

Question: A cycle tyre bursts suddenly. This represents an

[SCRA 1994]

Options:

A) $ 108^{o}C $

B) $ 9327^{o}C $

C) $ 1200^{o}C $

D) $ 927^{o}C $

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Answer:

Correct Answer: D

Solution:

$ T{{V}^{\gamma -1}}= $ constant$ \Rightarrow T _{2}=T _{1}{{( \frac{V _{1}}{V _{2}} )}^{\gamma -1}}=927^{o}C $



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