SATHEE: Thermodynamics Question 269

Thermodynamics Question 269

Question: The state of an ideal gas is changed through an isothermal process at temperature $T_{0}$ . The work done by gas in going from state B to C is double the work done by gas in going from state A to B. If the pressure in the state B is $P_{0} / 2$ then the pressure of the gas in state C is

Options:

A) $P_{0} / 2$

B) $P_{0} / 4$

C) $P_{0} / 6$

D) $P_{0} / 8$

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Work done by gas in going isothermally from stated to 5 is $Δ W_{A B} = n R T In \frac{P_{A}}{P_{B}} = n R T In 2$ ….(i)

Work done by gas in going isothermally from state B to C is $Δ W_{B C} = n R T In \frac{P_{B}}{P_{C}} = n R T \frac{P_{0}}{2 P_{C}}$ …(ii)

It is given that $Δ W_{B C} = 2 Δ W_{A B}$

$In \frac{P_{0}}{2 P_{C}} = In {(2)}^{2} ∴ P_{C} = \frac{P_{0}}{8}$

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Thermodynamics Question 269

Question: The state of an ideal gas is changed through an isothermal process at temperature T0 . The work done by gas in going from state B to C is double the work done by gas in going from state A to B. If the pressure in the state B is P0/2 then the pressure of the gas in state C is

Options:

Answer:

Solution:

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Question: The state of an ideal gas is changed through an isothermal process at temperature $T_{0}$ . The work done by gas in going from state B to C is double the work done by gas in going from state A to B. If the pressure in the state B is $P_{0} / 2$ then the pressure of the gas in state C is