Thermodynamics Question 263

Question: One mole of an ideal gas at an initial temperature of T K does 6R joules of word adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3, the final temperature of gas will be

Options:

A) $ (T-4)K $

B) $ (T+2.4)K $

C) $ (T-2.4)K $

D) $ (T+4)K $

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ T _{1}=T,W=6R\text{ joules},\gamma =\frac{5}{3} $

$ W=\frac{P _{1}V _{1}-P _{2}V _{2}}{\gamma -1}=\frac{nRT _{1}-nRT _{2}}{\gamma -1} $

$ =\frac{nR( T _{1}-T _{2} )}{\gamma -1} $

$ n=1,T _{1}=T\Rightarrow \frac{R( T-T _{2} )}{5/3-1}=6R $

$ \Rightarrow T _{2}=( T-4 )K $



NCERT Chapter Video Solution

Dual Pane