Thermodynamics Question 258

Question: The pressure inside a tyre is 4 times that of atmosphere. If the tyre bursts suddenly at temperature 300 K, what will be the new temperature?

Options:

A) $ 300{{( 4 )}^{772}} $

B) $ 300{{( 4 )}^{2/7}} $

C) $ 300{{( 2 )}^{772}} $

D) $ 300{{( 4 )}^{-2/7}} $

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Answer:

Correct Answer: D

Solution:

[d] Under adiabatic change $ \frac{T _{1}}{T _{2}}{{( \frac{P _{1}}{P _{2}} )}^{\frac{1-\gamma }{\gamma }}}\text{or}T _{2}=T _{1}{{( P _{1}/P _{2} )}^{\frac{1-\gamma }{\gamma }}} $

$ \therefore T _{2}=300{{(4/1)}^{\frac{1-( 7/5 )}{( 7/5 )}}}; $

$ \gamma =1.4=7/5\text{ for air} $

$ \text{or }T _{2}=300{{( 4 )}^{-2/7}} $



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