Thermodynamics Question 255

Question: For an ideal gas graph is shown for three processes, Process 1, 2 and 3 are respectively.

Options:

A) Isobaric, adiabatic isochoric

B) Adiabatic, isobaric, isochoric

C) Isochoric, adiabatic, isobaric

D) Isochoric, isobaric, adiabatic

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Isochoric proceess dV=0

W=0 proceess 1 Isobaric: W=PΔV=nRAT

Adiabatic |W|=nRΔTγ10<γ1<1 .

As work done in case of adiabatic process is more so process 3 is adiabatic and process 2 is isobaric.



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