Thermodynamics Question 251

Question: A closed system undergoes a process 12 for which the values W12 and Q12 are 50 kJ and - 20 kJ respectively. If the system is returned to state 1 and Q12+10kJ the work done W12 is

Options:

A) 40 kJ

B) 50 kJ

C) -60 kJ

D) -50 kJ

Show Answer

Answer:

Correct Answer: C

Solution:

[c] 20=ΔU+50ΔU=70.

From 21,ΔU=70kJ.

Now 10=70+WW=60kJ.



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