Thermodynamics Question 25

Question: A given system undergoes a change in which the work done by the system equals the decrease in its internal energy. The system must have undergone an

[Haryana CEE 1996; UPSEAT 2003]

Options:

A) 227.36 K

B) 500.30 K

C) 454.76 K

D) $ -47^{o}C $

Show Answer

Answer:

Correct Answer: A

Solution:

$ T{{V}^{\gamma -1}}= $ constant

Therefore $ \frac{T _{2}}{T _{1}}={{( \frac{V _{1}}{V _{2}} )}^{\gamma }} $

Therefore $ T _{2}=T _{1}{{( \frac{V _{1}}{V _{2}} )}^{\gamma }} $

$ \Rightarrow T _{2}=300{{( \frac{1}{2} )}^{0.4}}=227.36\ K $



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