Thermodynamics Question 248
Question: A thermodynamic system undergoes cyclic process ABCDA as shown in fig. The work done by the system in the cycle is
Options:
A) $ P _{0}V _{0} $
B) $ 2P _{0}V _{0} $
C) $ \frac{P _{0}V _{0}}{2} $
D) Zero
Show Answer
Answer:
Correct Answer: D
Solution:
[d] Work done by the system in the cycle =Area under P-V curve and V-axis $ =\frac{1}{2}( 2P _{0}-P _{0} )( 2V _{0}-V _{0} )+ $
$ [ -( \frac{1}{2} )( 3p _{0}-2p _{0} )( 2V _{0}-V _{0} ) ] $
$ =\frac{P _{0}V _{0}}{2}-\frac{P _{0}V _{0}}{2}=0 $
