SATHEE: Thermodynamics Question 247

Thermodynamics Question 247

Question: When a system is taken a from state i to state f along the path iaf, it is found that $Q = 50$ cal and $W = 20 c a l .$ , Along the path ibf $Q = 36$ cal. W along the path ibf is

Options:

A) 14 cal

B) 6 cal

C) 16 cal

D) 66 cal

Show Answer

Answer:

Correct Answer: B

Solution:

[b] For path iaf, $Q = 50 c a l W = 20 c a l$

By first law of thermodynamics, $Δ U = Q - W = 50 - 20 = 30 c a l .$ For path ibf $Q^{'} = 36 c a l$

$W = ?$ or, $W = Q^{'} - Δ U^{'}$

Since, the change in internal energy does not depend on the path,

therefore $Δ U^{'} = 30 c a l$

$∴ W = Q^{'} - Δ U^{'} = 36 - 30 = 6 c a l .$

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Thermodynamics Question 247

Question: When a system is taken a from state i to state f along the path iaf, it is found that Q=50 cal and W=20cal. , Along the path ibf Q=36 cal. W along the path ibf is

Options:

Answer:

Solution:

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Question: When a system is taken a from state i to state f along the path iaf, it is found that $Q = 50$ cal and $W = 20 c a l .$ , Along the path ibf $Q = 36$ cal. W along the path ibf is