Thermodynamics Question 247

Question: When a system is taken a from state i to state f along the path iaf, it is found that $ Q=50 $ cal and $ W=20cal. $ , Along the path ibf $ Q=36 $ cal. W along the path ibf is

Options:

A) 14 cal

B) 6 cal

C) 16 cal

D) 66 cal

Show Answer

Answer:

Correct Answer: B

Solution:

[b] For path iaf, $ Q=50cal~~W=20cal $

By first law of thermodynamics, $ \Delta U=Q-W=50-20=30cal. $ For path ibf $ Q’=36cal $

$ W=? $ or, $ W=Q’-\Delta U’ $

Since, the change in internal energy does not depend on the path,

therefore $ \Delta U’=30cal $

$ \therefore W=Q’-\Delta U’=36-30=6cal. $



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