Thermodynamics Question 245

Options:

A) isothermal curve slope = adiabatic curve slope

B) isothermal curve slope =$ \gamma $ $ \times $ adiabatic curve slope

C) adiabatic curve slope =$ \gamma $$ \times $ isothermal curve slope

D) adiabatic curve slope =$ \frac{1}{2} $$ \times $ isothermal curve slope

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Answer:

Correct Answer: C

Solution:

[c] $ \frac{\text{Slope of adiabatic curve}}{\text{Slope of isothermal curve}} $

$ \text{=}\frac{{{( dP/dV )} _{adi}}}{{{( dP/dV )} _{iso}}}=+\gamma $

So slop to adiabatic curve is $ \gamma ( =\frac{C _{P}}{C _{V}} ) $ times of isothermal curve.



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