SATHEE: Thermodynamics Question 232

Thermodynamics Question 232

Question: 110 joules of heat is added to a gaseous system, whose internal energy is 40J; then the amount of external work done is

Options:

A) 150 J

B) 70 J

C) 110 J

D) 40 J

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $Δ Q = Δ U + Δ W$

$\Rightarrow Δ W = Δ Q - Δ U = 110 - 40 = 70 J$

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Thermodynamics Question 232

Question: 110 joules of heat is added to a gaseous system, whose internal energy is 40J; then the amount of external work done is

Options:

Answer:

Solution:

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