Thermodynamics Question 232
Question: 110 joules of heat is added to a gaseous system, whose internal energy is 40J; then the amount of external work done is
Options:
A) 150 J
B) 70 J
C) 110 J
D) 40 J
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ \Delta Q=\Delta U+\Delta W $
$ \Rightarrow \Delta W=\Delta Q-\Delta U=110-40=70J $
