Thermodynamics Question 23

Question: For adiabatic processes (γ=CpCv)

[KCET 1999; MP PET 1995; CPMT 2003]

Options:

A) 8Po

B) 16P0

C) 6Po

D) 2Po

Show Answer

Answer:

Correct Answer: B

Solution:

P2P1=(V1V2)γ

Therefore P2=P1(V1V2)γ=P0(8)4/3=16P0.



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