SATHEE: Thermodynamics Question 226

Thermodynamics Question 226

Question: In a given process on an ideal gas, $d W = 0$ and $d Q < 0.$ Then for the gas

Options:

A) the temperature will decrease

B) the volume will increase

C) the pressure will remain constant

D) the temperature will increase

Show Answer

Answer:

Correct Answer: A

Solution:

[a] From the first law of thermodynamics

$d Q = d U + d W$ Here $d W = 0$ (given) $∴ d Q = d U$

Now since $d Q < 0$ (given)

$∴ d Q$ is negative

$\Rightarrow d U = - v e \Rightarrow d U decreases .$

$\Rightarrow$ Temperature decreases.

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Thermodynamics Question 226

Question: In a given process on an ideal gas, dW=0 and dQ<0. Then for the gas

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

Question: In a given process on an ideal gas, $d W = 0$ and $d Q < 0.$ Then for the gas