Thermodynamics Question 226

Question: In a given process on an ideal gas, $ dW=0 $ and $ dQ<0. $ Then for the gas

Options:

A) the temperature will decrease

B) the volume will increase

C) the pressure will remain constant

D) the temperature will increase

Show Answer

Answer:

Correct Answer: A

Solution:

[a] From the first law of thermodynamics

$ dQ=dU+dW $ Here $ dW=0 $ (given) $ \therefore ~dQ=dU $

Now since $ dQ<0 $ (given)

$ \therefore dQ $ is negative

$ \Rightarrow dU=-ve\Rightarrow dU\text{ decreases}\text{.} $

$ \Rightarrow $ Temperature decreases.



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