Thermodynamics Question 217
Question: When 1 gm of water at $ 0^{o}C $ and $ 1\times 10^{5}\ N/m^{2} $ pressure is converted into ice of volume $ 1.091\ cm^{2} $ , the external work done will be
Options:
A) 0.0091 joule
B) 0.0182 joule
C) ? 0.0091 joule
D) ? 0.0182 joule
Show Answer
Answer:
Correct Answer: A
Solution:
It is an isothermal process.
Hence work done $ =P(V _{2}-V _{1}) $
$ =1\times 10^{5}\times (1.091-1)\times {{10}^{-6}}=0.0091\ J $
