Thermodynamics Question 202

Question: Work done per mol in an isothermal change is

[RPMT 2004; BCECE 2005]

Options:

A) $ RT{\log _{10}}\frac{V _{2}}{V _{1}} $

B) $ RT{\log _{10}}\frac{V _{1}}{V _{2}} $

C) $ RT{\log _{e}}\frac{V _{2}}{V _{1}} $

D) $ RT{\log _{e}}\frac{V _{1}}{V _{2}} $

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Answer:

Correct Answer: C

Solution:

For isothermal process $ PV=RT\Rightarrow P=\frac{RT}{V} $

$ \therefore $ W$ =PdV=\int _{V _{1}}^{V _{2}}{\frac{RT}{V}dV=RT}{\log _{e}}\frac{V _{2}}{V _{1}} $



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