Thermodynamics Question 199
Question: For an isothermal expansion of a perfect gas, the value of $ \frac{\Delta P}{P} $ is equal
[CPMT 1980]
Options:
A) $ -{{\gamma }^{1/2}}\frac{\Delta V}{V} $
B) $ -\frac{\Delta V}{V} $
C) $ -\gamma \frac{\Delta V}{V} $
D) $ -{{\gamma }^{2}}\frac{\Delta V}{V} $
Show Answer
Answer:
Correct Answer: B
Solution:
Differentiate $ PV= $ constant w.r.t V
Therefore $ P\Delta V+V\Delta P=0 $
Therefore $ \frac{\Delta P}{P}=-\frac{\Delta V}{V} $
