SATHEE: Thermodynamics Question 178

Thermodynamics Question 178

Question: Work done by 0.1 mole of a gas at $27^{o} C$ to double its volume at constant pressure is (R=2 cal mol-C)

[EAMCET 1994]

Options:

A) 54 cal

B) 600 cal

C) 60 cal

D) 546 cal

Show Answer

Answer:

Correct Answer: C

Solution:

$W = P Δ V = n R Δ T = 0.1 \times 2 \times 300 = 60 c a l$

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Thermodynamics Question 178

Question: Work done by 0.1 mole of a gas at 27oC to double its volume at constant pressure is (R=2 cal mol-C)

Options:

Answer:

Solution:

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Question: Work done by 0.1 mole of a gas at $27^{o} C$ to double its volume at constant pressure is (R=2 cal mol-C)