Thermodynamics Question 178
Question: Work done by 0.1 mole of a gas at $ 27^{o}C $ to double its volume at constant pressure is (R=2 cal mol-C)
[EAMCET 1994]
Options:
A) 54 cal
B) 600 cal
C) 60 cal
D) 546 cal
Show Answer
Answer:
Correct Answer: C
Solution:
$ W=P\Delta V=nR\Delta T=0.1\times 2\times 300=60\ cal $
