SATHEE: Thermodynamics Question 171

Thermodynamics Question 171

Question: An ideal gas heat engine operates in Carnot cycle between 227°C and 127°C. It absorbs $6 \times 10^{4}$ cals of heat at higher temperature. Amount of heat converted to work is

[CBSE PMT 2005]

Options:

A) $2.4 \times 10^{4}$ cal

B) $6 \times 10^{4}$ cal

C) $1.2 \times 10^{4}$ cal

D) $4.8 \times 10^{4}$ cal

Show Answer

Answer:

Correct Answer: C

Solution:

$η = \frac{T_{1} - T_{2}}{T_{1}} = \frac{W}{Q}$

Therefore $W = \frac{Q (T_{1} - T_{2})}{T_{1}}$

$= \frac{6 \times 10^{4} [(227 + 273) - (273 + 127)]}{(227 + 273)}$

$= \frac{6 \times 10^{4} \times 100}{500}$

$= 1.2 \times 10^{4} c a l$

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Thermodynamics Question 171

Question: An ideal gas heat engine operates in Carnot cycle between 227°C and 127°C. It absorbs 6×104 cals of heat at higher temperature. Amount of heat converted to work is

Options:

Answer:

Solution:

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Question: An ideal gas heat engine operates in Carnot cycle between 227°C and 127°C. It absorbs $6 \times 10^{4}$ cals of heat at higher temperature. Amount of heat converted to work is