Thermodynamics Question 168

Question: An ideal refrigerator has a freezer at a temperature of $ -13{}^\circ C. $ The coefficient of performance of the engine is 5. The temperature of the air (to which heat is rejected) will be

[BHU 2000; CPMT 2002]

Options:

A) 325°C

B) 325K

C) 39°C

D) 320°C

Show Answer

Answer:

Correct Answer: C

Solution:

Coefficient of performance $ K=\frac{T _{2}}{T _{1}-T _{2}} $

Therefore $ 5=\frac{(273-13)}{T _{1}-(273-13)}=\frac{260}{T _{1}-260} $

Therefore $ 5T _{1}-1300=260 $

Therefore $ 5T _{1}=1560 $

Therefore $ T _{1}=312K\to 39{}^\circ C $



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