Thermodynamics Question 167
Question: An ideal heat engine working between temperature T1 and T2 has an efficiency h, the new efficiency if both the source and sink temperature are doubled, will be
[DPMT 2000]
Options:
A) $ \frac{\eta }{2} $
B) $ \eta $
C) $ 2\eta $
D) $ 3\eta $
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Answer:
Correct Answer: B
Solution:
In first case $ {\eta _{1}}=\frac{T _{1}-T _{2}}{T _{1}} $ .
In second case $ {\eta _{2}}=\frac{2T _{1}-2T _{2}}{2T _{1}} $
$ =\frac{T _{1}-T _{2}}{T _{1}}=\eta $
