Thermodynamics Question 164

Question: Efficiency of a Carnot engine is 50% when temperature of outlet is 500 K. In order to increase efficiency up to 60% keeping temperature of intake the same what is temperature of outlet

[CBSE PMT 2002]

Options:

A) 200 K

B) 400 K

C) 600 K

D) 800 K

Show Answer

Answer:

Correct Answer: B

Solution:

η=1T2T1

Therefore 12=1500T1

Therefore 500T1=12 -..(i) 60100=1T2T1

Therefore T2T1=25 -..(ii) Dividing equation (i) by (ii), 500T2=54

Therefore T2=400K



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