Thermodynamics Question 161
Question: A carnot engine has the same efficiency between 800 K to 500 K and x K to 600 K. The value of x is
[Pb. PMT 1996; CPMT 1996]
Options:
A) 1000 K
B) 960 K
C) 846 K
D) 754 K
Show Answer
Answer:
Correct Answer: B
Solution:
In first case, $ ({\eta _{1}})=1-\frac{500}{800}=\frac{3}{8} $
and in second case, $ ({\eta _{2}})=1-\frac{600}{x} $
Since $ {\eta _{1}}={\eta _{2}}, $
therefore $ \frac{3}{8}=1-\frac{600}{x} $
or $ \frac{600}{x}=1-\frac{3}{8}=\frac{5}{8} $ or$ x=\frac{600\times 8}{5}=960K $
