Thermodynamics Question 157
Question: The temperature of reservoir of Carnot’s engine operating with an efficiency of 70% is 1000K. The temperature of its sink is
[DCE 2003]
Options:
A) 300 K
B) 400 K
C) 500 K
D) 700 K
Show Answer
Answer:
Correct Answer: A
Solution:
$ \eta =1-\frac{T _{2}}{T _{1}} $
Therefore $ \frac{70}{100}=1-\frac{T _{2}}{1000} $
Therefore $ T _{2}=300K $
