SATHEE: Thermodynamics Question 155

Thermodynamics Question 155

Question: A Carnot engine absorbs an amount Q of heat from a reservoir at an abosolute temperature T and rejects heat to a sink at a temperature of T/3. The amount of heat rejected is

[UPSEAT 2004]

Options:

A) Q / 4

B) Q / 3

C) Q / 2

D) 2Q / 3

Show Answer

Answer:

Correct Answer: B

Solution:

$∵ η = 1 - \frac{T_{2}}{T_{1}} = \frac{W}{Q_{1}}$

$T_{2} = 300 K$ where $Q_{1} =$ heat absorbed, $Q_{2} =$ heat rejected

Therefore $1 - \frac{T / 3}{T} = \frac{W}{Q_{1}}$

Therefore $\frac{2}{3} = \frac{W}{Q_{1}} = \frac{Q_{1} - Q_{2}}{Q_{1}}$

Therefore $\frac{2}{3} = 1 - \frac{Q_{2}}{Q_{1}}$

Therefore $\frac{Q_{2}}{Q_{1}} = \frac{1}{3}$

Therefore $Q_{2} = \frac{Q_{1}}{3} = \frac{Q}{3}$

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Thermodynamics Question 155

Question: A Carnot engine absorbs an amount Q of heat from a reservoir at an abosolute temperature T and rejects heat to a sink at a temperature of T/3. The amount of heat rejected is

Options:

Answer:

Solution:

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