[Pb. PET 2000]
A) $ T _{2}=273K $
B) $ T _{2}=0K $
C) $ T _{1}=273K $
D) $ T _{1}=0K $
Correct Answer: B
$ \eta =1-\frac{T _{2}}{T _{1}} $ for 100% efficiency h = 1 which gives T2 = 0 K.
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