Thermodynamics Question 151
Question: An ideal gas heat engine operates in a Carnot’s cycle between $ 227^{o}C $ and $ 127^{o}C $ . It absorbs 6 × 104 J at high temperature. The amount of heat converted into work is ….
[KCET 2004]
Options:
A) $ 4.8\times 10^{4}J $
B) $ 3.5\times 10^{4}J $
C) $ 1.6\times 10^{4}J $
D) $ 1.2\times 10^{4}J $
Show Answer
Answer:
Correct Answer: D
Solution:
$ \eta =1-\frac{T _{2}}{T _{1}}=1-\frac{400}{500}=\frac{1}{5} $
$ \because \ \eta =\frac{W}{Q} $
Therefore $ \frac{1}{5}=\frac{W}{Q} $
Therefore $ W=\frac{Q}{5}=\frac{6}{5}\times 10^{4}=1.2\times 10^{4}J $
