SATHEE: Thermodynamics Question 145

Thermodynamics Question 145

Question: A Carnot engine working between $300 K$ and 600K has work output of 800 J per cycle. What is amount of heat energy supplied to the engine from source per cycle

[DPMT 1999; Pb. PMT 2002, 05; Kerala PMT 2004]

Options:

A) 1800 J/cycle

B) 1000 J/cycle

C) 2000 J/cycle

D) 1600 J/cycle

Show Answer

Answer:

Correct Answer: D

Solution:

$η = \frac{T_{1} - T_{2}}{T_{1}} - \frac{W}{Q}$

Therefore $Q = (\frac{T_{1}}{T_{1} - T_{2}}) W$

$= \frac{600}{(600 - 300)} \times 800$ =1600 J

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Thermodynamics Question 145

Question: A Carnot engine working between 300K and 600K has work output of 800 J per cycle. What is amount of heat energy supplied to the engine from source per cycle

Options:

Answer:

Solution:

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Question: A Carnot engine working between $300 K$ and 600K has work output of 800 J per cycle. What is amount of heat energy supplied to the engine from source per cycle